Difference between revisions of "2002 AMC 8 Problems/Problem 7"
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+ | == Problem == | ||
− | + | The students in Mrs. Sawyer's class were asked to do a taste test of five kinds of candy. Each student chose one kind of candy. A bar graph of their preferences is shown. What percent of her class chose candy E? | |
− | + | <asy> | |
+ | real[] r={6, 8, 4, 2, 5}; | ||
+ | int i; | ||
+ | for(i=0; i<5; i=i+1) { | ||
+ | filldraw((4i,0)--(4i+3,0)--(4i+3,2r[i])--(4i,2r[i])--cycle, black, black); | ||
+ | } | ||
+ | draw(origin--(19,0)--(19,16)--(0,16)--cycle, linewidth(0.9)); | ||
+ | for(i=1; i<8; i=i+1) { | ||
+ | draw((0,2i)--(19,2i)); | ||
+ | } | ||
+ | label("$0$", (0,2*0), W); | ||
+ | label("$1$", (0,2*1), W); | ||
+ | label("$2$", (0,2*2), W); | ||
+ | label("$3$", (0,2*3), W); | ||
+ | label("$4$", (0,2*4), W); | ||
+ | label("$5$", (0,2*5), W); | ||
+ | label("$6$", (0,2*6), W); | ||
+ | label("$7$", (0,2*7), W); | ||
+ | label("$8$", (0,2*8), W); | ||
+ | label("$A$", (0*4+1.5, 0), S); | ||
+ | label("$B$", (1*4+1.5, 0), S); | ||
+ | label("$C$", (2*4+1.5, 0), S); | ||
+ | label("$D$", (3*4+1.5, 0), S); | ||
+ | label("$E$", (4*4+1.5, 0), S); | ||
+ | label("SWEET TOOTH", (9.5,18), N); | ||
+ | label("Kinds of candy", (9.5,-2), S); | ||
+ | label(rotate(90)*"Number of students", (-2,8), W);</asy> | ||
+ | |||
+ | <math>\text{(A)}\ 5 \qquad \text{(B)}\ 12 \qquad \text{(C)}\ 15 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 20</math> | ||
+ | ==Solution== | ||
− | + | From the bar graph, we can see that <math>5</math> students chose candy E. There are <math>6+8+4+2+5=25</math> total students in Mrs. Sawyers class. The percent that chose E is <math>\frac{5}{25} \cdot 100 = \boxed{\text{(E)}\ 20}</math>. | |
+ | ==See Also== | ||
+ | {{AMC8 box|year=2002|num-b=6|num-a=8}} | ||
+ | {{MAA Notice}} |
Latest revision as of 00:41, 5 July 2013
Problem
The students in Mrs. Sawyer's class were asked to do a taste test of five kinds of candy. Each student chose one kind of candy. A bar graph of their preferences is shown. What percent of her class chose candy E?
Solution
From the bar graph, we can see that students chose candy E. There are total students in Mrs. Sawyers class. The percent that chose E is .
See Also
2002 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.